Consider two hot bodies B 1 and B 2- which have temperatures 100- C and 80- C respectively at t -0- The temperature of the surroundings is 40- C The ratio of the respective rates of cooling R 1 and R 2 of these two bodies at t -0 will beA- R1- R2-3- 2B- R1- R2-5- 4C- R1- R2-4- 5D- R1- R2-2- 3

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Byju's Answer

Standard VII

Physics

Conduction

Consider two ...

Question

Consider two hot bodies $B_{1}$ and $B_{2}$ . which have temperatures $100^{\circ} C$ and $80^{\circ} C$ respectively at t = 0 .The temperature of the surroundings is $40^{\circ} C$ . The ratio of the respective rates of cooling $R_{1} a n d R_{2}$ of these two bodies at t = 0 will be

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Solution

The correct option is A

Initially at t = 0

Rate of cooling (R) µ Fall in temperature of body (q - $q_{0}$ )

$\Rightarrow \frac{R_{1}}{R_{2}} = \frac{θ_{1} - θ_{0}}{θ_{2} - θ_{0}} = \frac{100 - 40}{80 - 40} = \frac{3}{2}$

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Consider two hot bodies B1 and B2. which have temperatures 100∘C and 80∘C respectively at t = 0 .The temperature of the surroundings is 40∘C. The ratio of the respective rates of cooling R1 and R2 of these two bodies at t = 0 will be

The correct option is A Initially at t = 0 Rate of cooling (R) µ Fall in temperature of body (q - q0) ⇒R1R2=θ1−θ0θ2−θ0=100−4080−40=32

Consider two hot bodies $B_{1}$ and $B_{2}$ . which have temperatures $100^{\circ} C$ and $80^{\circ} C$ respectively at t = 0 .The temperature of the surroundings is $40^{\circ} C$ . The ratio of the respective rates of cooling $R_{1} a n d R_{2}$ of these two bodies at t = 0 will be

The correct option is A

Initially at t = 0

Rate of cooling (R) µ Fall in temperature of body (q - $q_{0}$ )

$\Rightarrow \frac{R_{1}}{R_{2}} = \frac{θ_{1} - θ_{0}}{θ_{2} - θ_{0}} = \frac{100 - 40}{80 - 40} = \frac{3}{2}$