Consider two numbers in which one number is twice the other number minus 5. The sum of these numbers is represented as .

3 x - 5

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3 x + 5

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2 x - 5

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x - 5

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Solution

The correct option is A $3 x - 5$
If one number is $x$ , then the other number is $2 x - 5$ .

The sum of these numbers is then
$x + (2 x - 5) = x + 2 x - 5 = 3 x - 5$

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