The correct option is D acceleration of the block
Due to relative motion between observers, they will find the block moving the different speeds.
∴Kinetic energy observed by each observer will be different at any time t.
⇒The direction of motion of block is not given w.r.t to observers, hence they may observe different work done by friction on the block.
⇒Velocity of block as observed by both observers are different. So for them ΔK.E will be different. Hence, from work-energy theorem the net workdone on block won't be same for both observers.
∵ Both observers are moving with constant speed, hence the rate of change of velocity of block with respect to time will be zero, as observed by any of the observer.
∴→ablock, observer=0=constant
⇒Option (d) is correct.