Consider two particles P and Q. Particle P moves from A to B and particle Q moves from C to D. If the displacement of particle P and Q be x, y respectively. Then:
A
x=y
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B
x<y
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C
x>y
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D
x≥y
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Solution
The correct option is Cx>y when particle P moves from A to B, from the given figure we can see that its displacement is AB.
From right angled triangle, ΔOAB: AB=√(OA)2+(OB)2 ⇒AB=√(2)2+(5)2=√29m ⇒x=AB=√29m
when particle Q moves from C to D, from the given figure we can see that its displacement is CD.
From right angled triangle, ΔODC: CD=√(OC)2+(OD)2 ⇒CD=√(3)2+(4)2=√25=5m ⇒y=CD=5m
Hence x>y