Consider two ratios 3:5 and x:7. Find the largest value of x for which x:7 is less than 3:5.

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Solution

Cross multiplying the ratios, we get the products:
21(=37) and 5x(=5x).

For x:7 < 3:5, 5x should be less than 21.
Recalling multiplication table, we realise for x = 4 or less than 4, 5x < 21.
Therefore, largest value of x should be equal to 4.

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