Consider two rectangles ABCD and PQRS lying between same parallels as shown in figure. If CD = 10cm and SR = 3cm. Then find the ratio of area of rectangle ABCD to the area of rectangle PQRS?

\frac{3}{10}

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\frac{10}{3}

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\frac{9}{100}

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\frac{100}{9}

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Solution

The correct option is B $\frac{10}{3}$

Since, Rectangle ABCD and PQRS is lying between same parallels, These ratio of areas can be written as
$\frac{a r e a (A B C D)}{a r e a (P Q R S)} = \frac{C D}{S R} = \frac{10}{3}$

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Consider two rectangles ABCD and PQRS lying between same parallels as shown in figure. If CD = 10cm and SR = 3cm. Then find the ratio of area of rectangle ABCD to the area of rectangle PQRS?

The correct option is B 103 Since, Rectangle ABCD and PQRS is lying between same parallels, These ratio of areas can be written as area(ABCD)area(PQRS)=CDSR=103

The correct option is B $\frac{10}{3}$

Since, Rectangle ABCD and PQRS is lying between same parallels, These ratio of areas can be written as
$\frac{a r e a (A B C D)}{a r e a (P Q R S)} = \frac{C D}{S R} = \frac{10}{3}$