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Question

Considering an ideal refrigerator, heat from its inside at a temperature of 277 K is transferred to a room at temperature of 300 K. Find the amount of heat extracted for each Joule of electrical energy consumed by refrigerator.

A
1 J
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B
1.3 J
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C
12 J
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D
15 J
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Solution

The correct option is C 12 J
From the definition of coefficient of performance for a Carnot refrigerator (ideal refrigerator),
β=Q2W=T2T1T2
Q2=W(T2T1T2) ...(i)
T2=277 K, T1=300 K
W=Electrical work consumed by refrigerator
W=1 J
From Eq.(i) we get,
Q2=1×277300277=12 J
Hence amount of heat extracted by the refrigerator will be 12 J

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