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Question

# Considering an ideal refrigerator, heat from its inside at a temperature of 277 K is transferred to a room at temperature of 300 K. Find the amount of heat extracted for each Joule of electrical energy consumed by refrigerator.

A
1 J
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B
1.3 J
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C
12 J
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D
15 J
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Solution

## The correct option is C 12 JFrom the definition of coefficient of performance for a Carnot refrigerator (ideal refrigerator), β=Q2W=T2T1−T2 ⇒Q2=W(T2T1−T2) ...(i) T2=277 K, T1=300 K W=Electrical work consumed by refrigerator W=1 J From Eq.(i) we get, Q2=1×277300−277=12 J Hence amount of heat extracted by the refrigerator will be 12 J

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