Question

Considering bohr's model to be valid for lithium atom, Energy associated with its valency electron can be given for various transitions. This valency electrons of 1st orbit. [Neglect energy of electrons of 1st orbit]
$\begin{array}{cccc}\left(P\right)& \text{Energy of atom in ground state}.& \left(1\right)& -3.4ev\\ \left(q\right)& \text{Energy of photon released in transition from}.& & \\ & \text{2nd excited state to ground state}.& \left(2\right)& -13.6ev\\ \left(r\right)& \text{Energy of 1st excited state}.& \left(3\right)& 12.1ev\\ \left(s\right)& \text{sonization energy of valency electron}.& \left(4\right)& 13.6ev\end{array}$

• A. p $\to$ 2, q $\to$ 2, r $\to$ 1, s $\to$ 5
• B. p $\to$ 5, q $\to$ 2, r $\to$ 1, s $\to$ 2
• C. p $\to$ 2, q $\to$ 5, r $\to$ 1, s $\to$ 2
• D. p $\to$ 1, q $\to$ 2, r $\to$ 2, s $\to$ 5

Answer 1

The correct option is A p $\to$ 2, q $\to$ 2, r $\to$ 1, s $\to$ 5

Under given conditions, lithium atom becomes identical to hydrogen atom. Energy of hydrogen atom in any state is $E=-\frac{13.6}{n^2}$

For n = 1 ; ground state
n = 2 ; 1st excited state
n = 3 ; 2nd excited state
and so on and so forth