Considering Ellingham diagram, which of the following metals can be used to reduced alumina?

M g

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F e

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C u

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Z n

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Solution

The correct option is A $M g$
Considering Ellingham diagram, $M g$ metal can be used to reduced alumina.
The negative free energy change for the formation of $M g O$ from $M g$ is greater than that for the formation of $A l_{2} O_{3}$ from $A l$ .

Hence, $M g$ has greater tendency to undergo oxidation than $A l$ . Hence, $M g$ is oxidised and $A l_{2} O_{3}$ is reduced to $A l$ .
Note: More negative the value of $Δ G$ , the greater is the tendency, of the element to combine with oxygen.

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$E {^{0}}_{F e^{2 +} / F e} = - 0.44 V, E {^{0}}_{Z n^{2 +} / Z n} = - 0.76 V$
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