Question

Considering $H_{2}O$ as a weak field ligand, the number of unpaired electrons in ${\left[Mn\left(H_2{O}_6\right)\right]}^{2+}$ will be:
(Atomic no. of $Mn=25$)

• A. five
• B. two
• C. four
• D. three

Answer 1

The correct option is A five

$\left[Mn\right(H_{2}O{)}_6{]}^{2+}$

$M{n}^{+2}$ Outer orbital $\uparrow \uparrow \uparrow$

$3d$ $4s$ $4p$ $4d$

$\left[Mn\right(H_{2}O{)}_6{]}^{2+}$ $\uparrow \uparrow \uparrow$ $\uparrow \downarrow \uparrow \downarrow \uparrow \downarrow \uparrow \downarrow \uparrow \downarrow \uparrow \downarrow$

$d^{2}s{p}^3$