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Question

Considering H2O as weak field ligand, the number of unpaired electrons in [Mn(H2O)6]2+ will be:

[Atomic number of Mn=25]

A
5
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B
2
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C
4
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D
3
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Solution

The correct option is A 5
Electronic configuration of Mn is [Ar]4s23d5

In the complex, [Mn(H2O)6]2+, charge on H2O will be zero.

So electronic configuration of Mn+2 will be [Ar]4s03d5.

The 5 electrons in the d-shell will occupy 5-d orbitals making them all unpaired as shown.

No. of unpaired electrons in the above complex in the metal ion is 5.

502741_467358_ans.JPG

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