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VBT Tetrahedral vs Square Planar

Considering H...

Question

Considering $H_{2} O$ as a weak ligand, the number of unpaired electrons in $[M n (H_{2} O)_{6}]^{2 +}$ would be

A

4

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B

5

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C

2

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D

3

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Solution

The correct option is B 5
$M n^{2 +}$ has $d^{5}$ configuration and the ligand is weak.

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Similar questions

H_{2} O

as a weak ligand, the number of unpaired electrons in

[M n (H_{2} O)_{6}]^{2 +}

H_{2} O

as a weak ligand, the number of unpaired electrons in

[M n (H_{2} O)_{6}]^{2 +}

H_{2} O

as a weak field ligand, the number of unpaired electrons in

[M n (H_{2} O)_{6}]^{2 +}

M n = 25)

H_{2} O

as weak field ligand, the number of unpaired electrons in

[M n (H_{2} O)_{6}]^{2 +}

will be:
(Atomic number of Mn=25):

H_{2} O

is a weak field ligand, the no. of unpaired electrons in

[M n (H_{2} O)_{6}]^{2 +}

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