Considering the angles shown below, .

a < b

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a > b

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

a = b

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B a > b
The larger is the angle, the more is the steepness of the slope.
In the given figures, the triangle with angle 'a' has more steeper slope than the triangle with angle 'b'.

Hence, angle 'a' is greater than angle 'b', or a > b.

Suggest Corrections

Similar questions

Δ H

I E_{1}

B a

Δ A^{'} C^{'} B

Δ A C B

c - b \neq 1, c + b \neq 1

\frac{(l o g_{c + b} a + l o g_{c - b} a)}{(2 l o g_{c + b} a \times l o g_{c - b} a)}

\tan x = \frac{b}{a}

\sqrt{\frac{a + b}{a - b}} + \sqrt{\frac{a - b}{a + b}}

a^{8} - 2 a^{4} b^{4} + b^{8}

Join BYJU'S Learning Program