Question

Considering the reaction sequence given below, the correct statement(s) is(are)

\( H _{3} COOH \frac{1 . Br _{2} \text {, red phospohorus }}{2 . H _{2} O } \longrightarrow P \) 1. 2. \( NnOH _{3 .} H _{3} \)

• A. $P$ can be reduced to a primary alcohol using ${\text{NaBH}}_4$.
• B. Treating $Q$ with a solution of ${\text{NaNO}}_2$ in aq. $\text{HCl}$ liberates ${\text{N}}_2$.
• C. $P$ is more acidic than ${\text{CH}}_3{\text{CH}}_2\text{COOH}$.
• D. Treating $P$ with conc. ${\text{NH}}_4\text{OH}$ solution followed by acidification gives $Q$.

Answer 1

Answer: (B), (C), (D)

Treating $P$ with conc. ${\text{NH}}_4\text{OH}$ solution followed by acidification gives $Q$.

\( \frac{1 . Br _{2} \text {, red phospohorus }}{2 . H _{2} O } \) (A) 1. \( P \) 3. \( H _{3} O ^{+} \) 0
(B) \( \underset{2 . H _{2} O }{\text { 1. Conc. } NH _{4} OH } \) (C) \( \stackrel{ NaNO _{2} / HCl }{\longrightarrow} \) \( + N _{2} \) gas \( Q \) (D) [P] is more acidic than \( CH _{3}- CH _{2}- COOH ^{3} \) due to \( -I \) effect of \( - Br \)