Question

Constant a quadrilateral $ABCD$, where $AB=4cm,BC=5cm,CD=6.5cm$ and $\angle B={105}^o$ and $\angle C={80}^o$

Answer 1

Step (1):-

First Draw a line $BC=5cm$

Step (2):-

Construct an angle $\angle CBY={105}^o$

Step (3):-

With B as centre and radius $4$ cm, draw an arc to cut line by at point A.

Step (4):-

Again, construct an angle $\angle BCZ={80}^o$

Step (5):-

With C as centre and a radius $6.5cm$ draw an arc to cut $CZ$ at point $D$.Join $AD$

Hence, $ABCD$ is the required quadrilateral.