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constant force acting on a body of mass 3.0 kg changes its speed from 2.0 m s¯¹ to 3.5 m s-¯¹ in 25 s. The direction of the motion of the body remains unchanged. What is the magnitude and direction of the force ?

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Solution

Given:The mass of the body is 3.0kg, theinitial speedof the body is 2.0m/s , the final speedof the body is 3.5m/s and the time taken is 25s.

Acceleration produced in the body can be calculated usingthe first equation of motion,

v=u+at

By substituting the given values in the above expression, we get

3.5m/s =2.0m/s +a( 25s ) a= 1.5m/s 25s =0.06m/s

From Newton’s second law of the motion,

F=ma

By substituting the values in the above expression, we get

F=( 3.0kg )( 0.06m/s ) =0.18N

Thus, aforce of 0.18Nis acting in the direction of motion of the body.


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