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Question

Constant term in the expansion of (x−1x)10 is

A
152
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B
152
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C
252
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D
252
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Solution

The correct option is A 252
(x1x)10
Tr+1=10Cr(x)10r(1x)r
=10Crx10r(1)rxr
=10Cr(1)rx102r
For constant term 102r=0
r=5
10Cr(1)5=10C5=(10!)5!5!
=252

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