Constant torque acting on a uniform circular wheel changes its angular momentum from $A$ to $4 A$ in $4$ seconds. The magnitude of this torque is

\frac{3 A}{4}

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A

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\frac{4 A}{3}

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\frac{A}{2}

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Solution

The correct option is A $\frac{3 A}{4}$
Torque = Rate of change of angular momentum.
$= \frac{A_{F} - A_{i}}{t i m e} = \frac{4 A - A}{4} = \frac{3 A}{4} N - m$

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