Question

Construct $3$ equations starting with the solution:

$y=4$

Answer 1

Formation of equation with one variable:

We have, $y=4$

Multiply both sides by $3$

$$\begin{gathered} 3\times y=3\times 4 \\ \Rightarrow 3y=12 \end{gathered}$$

Adding $5$ on both sides

$$\begin{gathered} 3y+5=12+5 \\ \Rightarrow 3y+5=17 \end{gathered}$$

Again, for $y=4$

Multiplying both sides by $10$

$$\begin{gathered} 10\times y=10\times 4 \\ \Rightarrow 10y=40 \end{gathered}$$

Subtracting $3$ from both sides

$$\begin{gathered} 10y-3=40-3 \\ \Rightarrow 10y-3=37 \end{gathered}$$

Again, for $y=4$

Dividing both sides by $5$

$\frac{y}{5}=\frac{4}{5}$

Hence, the $3$ equations can be: $3y+5=17$, $10y-3=37$ and $\frac{y}{5}=\frac{4}{5}$.