The elements of a 3×3matrix are: A=⎡⎢⎣a11a12a13a21a22a23a31a32a33⎤⎥⎦
[0.5 Marks]
Applying the given rule: aij=0, if i≠j, and aij=i×j, if i=j
a11=1,a12=0,a13=0a21=0,a22=4,a23=0a31=0,a32=0,a33=9
[1 Mark]
Therefore A=⎡⎢⎣100040009⎤⎥⎦ is the required matrix.
[0.5 Marks]