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Question

Construct a 3×4 matrix whose elements aij are given by aij=i+2j

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Solution

The elements of a 3×4 matrix are A=a11a12a13a14a21a22a23a24a31a32a33a34

Applying the given rule: aij=i+2ja11=3,a12=5,a13=7,a14=9a21=4,a22=6,a23=8,a24=10a31=5,a32=7,a33=9,a34=11

Therefore A=35794681057911 is the required matrix.


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