Question

Construct a ∆ABC in which AB = 7 cm, ∠A = 45° and ∠C = 75°.

Answer 1

$$\begin{gathered} \mathrm{By}\mathrm{angle}\mathrm{sum}\mathrm{property}: \\ \angle B=180°-\angle A-\angle C \\ =180°-45°-75° \\ =60° \\ \begin{array}{l}\text{Steps of construction:}\\ \text{1}\text{. Draw AB=7cm}\\ \text{2 Draw ∠BAX= 45°}\\ 3.\text{Draw ∠ABY= 60°}\\ \text{4.The ray AX and BY intersect at C.}\end{array} \\ \text{Then, ABC is the required triangle.} \end{gathered}$$