Construct a ∆ABC in which ∠B = 60°, ∠C = 45° and the length of perpendicular from vertex A to base BC as 5 cm.

Open in App

Solution

Steps of construction:
1. Draw a line XY.
2. Take a point D on XY and draw PD $⊥$ XY.
3. Along PD, set off DA = 5 cm.
4. Draw a line LM $∥$ XY.
5. Draw $∠$ LAB = 60 $°$ and $∠$ MAC = 45 $°$ meeting XY at B and C, respectively.
Thus, $∆$ ABC is the required triangle.

Suggest Corrections

Similar questions

$C o n s t r u c t a Δ A B C i n w h i c h ∠ B = 45^{\circ}, ∠ C = 60^{\circ}, and the perpendicular from the vertex A to base BC is 4.5cm$

A B C

B C = 6

B = 60^{0}

A

B C = 25

A B C

B C = 54

A B C = 60^{0}

A

B C = 30

∠

45^{\circ}

Join BYJU'S Learning Program