Question

Construct a ∆ABC in which BC = 5.2 cm, ∠B = 30° and the difference of the other two sides is 3.5 cm.

Answer 1

Steps of construction:
1. Draw a line segment BC = 5.2 cm.
2. Construct $\angle$CBX = 30$°$.
3. Set off BP = 3.5 cm.
4. Join PC.
5. Draw the right bisector of PC, meeting BP produced at A.
6. Join AC.
Thus, $△$ABC is the required triangle.