Construct a ∆ABC in which BC = 5.2 cm, ∠B = 30° and the difference of the other two sides is 3.5 cm.

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Solution

Steps of construction:
1. Draw a line segment BC = 5.2 cm.
2. Construct $∠$ CBX = 30 $°$ .
3. Set off BP = 3.5 cm.
4. Join PC.
5. Draw the right bisector of PC, meeting BP produced at A.
6. Join AC.
Thus, $△$ ABC is the required triangle.

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