Question

Construct a ∆ABC in which BC = 5 cm, CA = 6 cm and AB = 7 cm. Construct a ∆A' BC' similar to ∆ABC, each of whose sides is $\frac{7}{5}$ times the corresponding sides of ∆ABC.

Answer 1

Steps of Construction :

Step 1. Draw a line segment BC = 5 cm.
Step 2. With B as centre and radius of 7 cm, cut an arc.
Step 3. With C as centre and radius of 6 cm, cut an arc. Name the point of intersection A.
Step 4. Join AB and AC.
Thus, △ABC is obtained .
Step 5. Extend BC to C', such that BC' = $\frac{7}{5}$ BC = $\frac{7}{5}$(5) cm = 7 cm.
Step 6. Draw A'C' ∥ AC, cutting BA produced at A'.

Thus, △A'BC'is the required triangle, each of whose sides is $\frac{7}{5}$ the corresponding sides of ∆ABC.