Construct a ∆ ABC such that AB = 6 cm, BC = 4.5 cm and AC = 5.5 cm. Construct a circumcircle of this triangle

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Solution

Steps of Construction:
1. Construct a line segment BC = 4.5 cm.
2. Taking B as centre and 6 cm radius construct an arc.
3. Taking C as centre and 5.5 cm radius construct another arc which intersects the first arc at point A.
4. Now join AB and AC
Therefore, ∆ ABC is the required triangle.
5. Construct a perpendicular bisector of AB and AC which intersect each other at the point O.
6. Now join OB, OC and OA.
7. Taking O as centre and radius OA construct a circle which passes through the points A, B and C.
This is the required circumcircle of ∆ ABC.

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