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Kohlrausch Law

Construct a c...

Question

Construct a cell from ${N i}^{2 +} ∣ ∣ N i a n d {C u}^{2 +} ∣ ∣ C u$ half cells. Write the cell reaction and calculate
the standard of the cell. ${E^{0}}_{N i} = - 0.236 V$ and ${E^{0}}_{C u} = 0.377$

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Solution

${C u}^{2 +} + N i ⟶ {N i}^{2 +} + C u {E^{0}}_{c e l l} = {E^{0}}_{c a t h o d e} - {E^{0}}_{a n o d e} = {E^{0}}_{{C u}^{2 +} / C u} - {E^{0}}_{{N i}^{2 +} / N i} = 0.377 - (- 0.236) = 0.613 V$
But the actual values are
${C u}^{2 +} / C u = 0.34 {N i}^{2 +} / N i = - 0.233 ∴ E_{c e l l} = 0.573 V$

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Similar questions

Q. Determine the standard emf of the cell and standard free energy change of the cell reaction

Z n | Z n^{2 +} | | N i^{2 +} | N i

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- 0.76 V

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Q. The standard reduction potential of the half cells at

298 K

N i^{2 +} (a q) + 2 e^{-} \to N i (s); E^{o} = - 0.28 V

M g^{2 +} (a q) + 2 e^{-} \to M g (s); E^{o} = - 2.37 V

The standard cell potential for a voltaic cell constructed using the two half reaction is

Q. Calculate the

E

E^{\circ}

N i | N i^{2 +} | | C u^{2 +} | C u

from the following half-cell reactions:

N i^{2 +} + 2 e^{-} \to N i; E^{\circ} = - 0.25 v o l t

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