Construct a circumcircle of a right angled triangle with sides $8 c m, 6 c m$ and $10 c m$ .

Open in App

Solution

Step 1: Draw $A B = 8 c m$
${A C}^{2} = {A B}^{2} + {A C}^{2}$
$\Rightarrow A C = \sqrt{8^{2} + 6^{2}} = 10 c m$
$∴$ Draw a right triangle $A B C$
Step 2: Construct a bisector of all three sides, they will meet at a common point.
Step 3: Draw the circle with radius as the intersection point of the bisectors that pass through one of the vertex.

Suggest Corrections

Similar questions

Q. Construct a incircle of a right angled triangle with sides

8 c m, 6 c m

and

10 c m

Q. Construct isosceles triangle with sides

6 c m, 6 c m, 8 c m

. Construct circumcircle of it. Then the measure of circumradius is :

Draw the circumcircle of a triangle with sides 6 cm, 8 cm and 10 cm. What is the radius of this circle?

What is the area of a right angled triangle if its sides are 6cm, 8cm and 10cm?

Draw a triangle with sides 6cm, 8cm and 10cm. Using a common vertex and with the 10cm side, construct a similar triangle with the ratio of corresponding sides 2:1.

Join BYJU'S Learning Program

Construct a circumcircle of a right angled triangle with sides 8 cm,6 cm and 10 cm.

Step 1: Draw AB=8cmAC2=AB2+AC2⇒AC=√82+62=10cm∴ Draw a right triangle ABCStep 2: Construct a bisector of all three sides, they will meet at a common point.Step 3: Draw the circle with radius as the intersection point of the bisectors that pass through one of the vertex.

Construct a circumcircle of a right angled triangle with sides $8 c m, 6 c m$ and $10 c m$ .