Construct a circumcircle of $∆$ ABC such that AB = 5 cm, AC = 12 cm, $∠$ BAC = 90 $°$ .

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Solution

Steps of construction:-
1. Draw a line segment AB= 5 cm.
2. Draw an angle $∠ BAX = 90 °$ .
3. With A as the centre and a radius of 12 cm, draw an arc cutting AX at C.
4. Join BC.
5. Then $△$ ABC is the required triangle.
6. Draw perpendicular bisectors of AC and AB (any two sides) which intersect at I.
7. Taking I as the centre and a radius equal to IA or IB or IC, draw the required circumcircle.

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