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Question

Construct a cyclic quadrilateral XYZW such that XY=4.8 cm,YZ=6.4 cm,ZXY=25 and XZW=40. Then, length of the shorter diagonal is:

A
12.9 cm
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B
13.5 cm
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C
10.4 cm
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D
11.2 cm
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Solution

The correct option is C 10.4 cm
  • Draw a line segment XY of length 4.8cm
  • From X, draw a line at 25o from XY.
  • From Y mark an arc of length of 6.4cm. The arc cuts the line at 25o from XY at Z.
  • These perpendiculars intersect each other at O.
  • Taking O as center, draw a circle of radius OX. This circle touches X,Y and Z.
  • From Z draw a line at angle of 40o with base XZ. This line cuts the circle at point W.
  • Join XYZW

Length of shorter diagonal =10.4cm (measurement)
892152_584220_ans_cd2349cb910b442dab733b34bee3927c.png

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