Question

Construct a ΔABC in which AB = 5 cm. ∠B = 60° altitude CD = cm. Construct a ΔAQR similar to ΔABC such that side ΔAQR is 1.5 times that of the corresponding sides of ΔACB

Answer 1

Given that

Construct a trianglein which and then a triangle similar to it whose sides are of the corresponding sides of.

We follow the following steps to construct the given

Step of construction

Step: I- First of all we draw a line segment.

Step: II- With B as centre and draw an angle.

Step: III -From point A and B construct which cut the line BS at point C

Step: IV- Join AC to obtain.

Step: V- Below AB, makes an acute angle.

Step: VI- Along AX, mark off five points such that

Step: VII -Join.

Step: VIII -Since we have to construct a triangle each of whose sides is of the corresponding sides of.

So, we draw a line on AX from point which is and meeting AB at Q.

Step: IX- From Q point draw and meeting AC at R

Thus, is the required triangle, each of whose sides is of the corresponding sides of.