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Question

Construct a frequency table with equal class intervals from the following data on the monthly wages (in rupees) of 28 labourers working in a factory, taking one of the class intervals as 210-230 (230 not included):

220, 268, 258, 242, 210, 268, 272, 242, 311, 290, 300, 320, 319, 304, 302, 318, 306, 292, 254, 278, 210, 240, 280, 316, 306, 215, 256, 236.

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Solution

Here, the maximum and minimum values of the variate are 320 and 210 respectively.

So the range = 320 – 210 = 110

Here, we will take class size 20 (As one class interval is 210–230).

Therefore, the frequency distribution in which the lower limit is included and upper limit excluded is:


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