Construct a histogram for the marks obtained by 100 students in the Class VII annual examinations shown below.
In the given frequency distribution, class lengths are different. So, we calculate the adjusted frequency for each class.
Here, least class length (50 to 60)=10
We use the formula,
Adjusted frequency of a class =Frequency of classLength of that class×Least class length
The modified table for frequency distribution is given below.
Marks scored (Class interval)Number of studentsClass lengthHeight of the bar0−3528352835×10=835−5012151215×10=850−6016101610×10=1660−10044404440×10=11
Along the horizontal axis, we represent the class intervals of marks on some suitable scale.
The corresponding frequencies of the number of students are represented along the Y-axis on a suitable scale.
Now, we draw rectangles with class intervals as the bases and the corresponding adjusted frequencies as heights.
A histogram of the given distribution is given below.
In the given frequency distribution, class lengths are different. So, we calculate the adjusted frequency for each class.
Here, least class length (50 to 60)=10
We use the formula,
Adjusted frequency of a class =Frequency of classLength of that class×Least class length
The modified table for frequency distribution is given below.
Marks scored (Class interval)Number of studentsClass lengthHeight of the bar0−3528352835×10=835−5012151215×10=850−6016101610×10=1660−10044404440×10=11
Along the horizontal axis, we represent the class intervals of marks on some suitable scale.
The corresponding frequencies of the number of students are represented along the Y-axis on a suitable scale.
Now, we draw rectangles with class intervals as the bases and the corresponding adjusted frequencies as heights.
A histogram of the given distribution is given below.
