Question

Construct a ‘more than’ cumulative frequency table and draw an ogive for the data given below:

Marks	1 - 10	11 - 20	21 - 30	31 - 40	41 - 50	51 - 60	61 - 70	71 - 80
Frequency	3	8	12	14	10	6	5	2

• A. (10, 60) (10.5, 55) (20.5, 49) (6, 37) (40.5, 23) (50.5, 13) (60.5, 7) (70.5,2)
• B. (0.5, 60) (10.5, 57) (20.5, 49) (30.5,37) (40.5, 23) (50.5, 13) (60.5, 7) (70.5,2)
• C. (0.5, 60) (10.5, 57) (20, 49) (30, 37) (40.5, 23) (50.5, 13) (60, 5) (70.5,2)
• D. (5, 60) (10, 57) (20, 47) (30.5, 39) (40.5, 23) (50.5, 13) (60.5, 7) (70.5, 2)

Answer 1

The correct option is B (0.5, 60) (10.5, 57) (20.5, 49) (30.5,37) (40.5, 23) (50.5, 13) (60.5, 7) (70.5,2)

MARKS	FREQUENCY
1 - 10
11 - 20	8
21 - 30	12
31 - 40	14
41 - 50	10
51 - 60	6
61 - 70	5
71 - 80	2
TOTAL	60

MARKS	FREQUENCY
0.5 - 10.5	3
10.5 - 20.5	8
20.5 - 30.5	12
30.5 - 40.5	14
40.5 - 50.5	10
50.5 - 60.5	6
60.5 - 70.5	5
70.5 - 80.5	2
TOTAL	60

MARKS	c.f
more than or equal to 0.5	60
more than or equal to 10.5	60 - 3 = 57
more than or equal to 20.5	57 - 8 = 49
more than or equal to 30.5	49 - 12 = 37
more than or equal to 40.5	37 - 14 = 23
more than or equal to 50.5	23 - 10 = 13
more than or equal to 60.5	13 - 6 = 7
more than or equal to 70.5	7 - 5 = 2

Plot the points (0⋅5, 60), (10⋅5, 57), (20⋅5, 49), (30⋅5, 37), (40⋅5, 23), (50⋅5, 13), (60⋅5, 7), (70⋅5, 2)



We plot the points

(0.5, 60)
(10.5, 57)
(20.5, 49)
(30.5, 37)
(40.5, 23)
(50.5, 13)
(60.5, 7)
(70.5, 2)