Question

Construct a parallelogram $ABCD$ in which $AB=5.2cm,BC=4.7cm$ and $AC=7.6cm$.

Answer 1

The given Parallelogram $ABCD$ can be drawn by following the steps.
Step $1$: Draw a line $AB=5.2cm$
Step $2$: Draw an arc of $4.7cm$ from $B$
Step $3$: From $A$ take radius of $7.6cm$ and cut the arc drawn in step $2$ and that point of intersection is $C$. Join $BC$ and $AC$.
Step $4$: Draw another arc from $A$ with $4.7cm$ as radius.
Step $5$: From $B$ take $7.6cm$ and cut the arc drawn in step $4$ and the point of intersection is $D$. now join $CD$ and $AD$.
We get the required parallelogram $ABCD$