Question

Construct a parallelogram $ABCD$, in which diagonal $AC=3.8cm$, diagonal $BD=4.6cm$ and the angle between $AC$ and $BD$ is ${60}^{\circ }$.

Answer 1

The given Parallelogram $ABCD$ can be drawn by following the steps.
Step $1$: Draw a line $AC=3.8cm$
Step $2$: Bisect $AC$ at $O$.
Step $3$: At $O$ draw $\angle COX={60}^{\circ }$
Step $4$: Set the value $OB=2.3cm$ and $OD=2.3cm$ (divided the value $4.6$ into $2.3$ and $2.3$)
Step $5$: Now join $AB,BC,CD,DA$
We get the required parallelogram $ABCD$