Question

Construct a parallelogram $PQRS$ with $PQ=4.5cm,QR=3cm$ and $\angle PQR={60}^{\circ }$.

Answer 1

In paralleogram $PQRS$

$PS=QR=3$ cm and $PQ=RS=4.5$ cm

Steps for construction:

Step 1. Draw a line segment $PQ=4.5$ cm

Step 2. Construct an angle $\angle PQY={60}^{\circ }$ at $Q$.

Step 3. On the line $QY$, make $QR=3$ cm.

Step 4. With $P$ as centre and radius $=3$ cm, draw an arc.

Step 5. With $R$ as centre and radius $=4.5$ cm, draw an arc to cut the previous arc at $S$.

Step 6. Join $PS$ and $RS$

Hence, $PQRS$ is the required parallelogram.