Construct a parallelogram, whose two adjacent sides AB = 3.6 cm, BC = 4.6 cm and height corresponding to side BC = 2.6 cm. [3 MARKS]

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Solution

Steps : 1 Mark
Construction : 2 Marks

Steps of constructions :
1. Draw a line segment BC of length 4.6 cm.
2. At C Construct an angle of $90^{\circ}$ and draw $C P ⊥ B C$ .
3. From CP, cut an arc of radius 2.6 cm, let it be E.
4. Through E draw a perpendicular to CP to get $Q R ∥ B C$ .
5. With B as centre and radius AB = 3.6 cm, draw an arc which cuts QR at A.
6. With C as centre and radius CD = 3.6 cm, draw an arc which cuts QR at D.
7. Join BA and CD. ABCD is the required parallelogram.

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