Construct a quadrilateral ABCD in which AB = 2.9 cm, BC = 3.2 cm, CD = 2.7 cm, DA = 3.4 cm and ∠A = 70°.

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Solution

Steps of construction:
Step 1: Draw AB= $2.9 c m$
Step 2: Make $∠ A = 70^{\circ}$
Step 3: With A as the centre, draw an arc of $3.4 c m$ . Name that point as D.
Step 4: With D as the centre, draw an arc of $2.7 c m$ .
Step 5: With B as the centre, draw an arc of 3.2 cm, cutting the previous arc at C.
Step 6: Join CD and BC.
Then, $A B C D$ is the required quadrilateral.

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Similar questions

Construct a quadrilateral ABCD in which AB = 2.9 cm, BC = 3.2 cm, CD = 2.7 cm, DA = 3.4 cm and $∠ A = 70^{\circ}$ .

B E S T

B E = 2.9 c m, E S = 3.2 c m, S T = 2.7 c m, B T = 3.4 c m

∠ B = 57^{o}

A B C D

A B = 3.4 c m, B C = 4.2 c m, A D = 2.7 c m

∠ A B C = 60^{\circ}

l (C D) = ?

A B C D

A B = 3.4 c m, B C = 4.2 c m, A D = 2.7 c m

∠ A B C = 60^{\circ}

m ∠ A D C

= ?

A B C D

A B = 3.4 c m, B C = 4.2 c m, A D = 2.7 c m

∠ A B C = 60^{\circ}

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