Construct a quadrilateral ABCD in which AB=3.8 cm, BC=3.4, CD=4.5 cm,AD=5 cm, and $∠ B = 80^{\circ}$ .

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Solution

(i) Draw a line segment AB =3.8 cm.
(ii) At B, draw a ray BX making an angle of $80^{\circ}$ and cut off BC=3.4 cm.
(iii) With centre A and radius 5 cm and with centre C and radius4.5 cm, draw arcs which intersect each other at D.
(iv) Join CD and AD.

ABCD is the required quadrilateral.

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Similar questions

∠ B = 80^{\circ} .

Construct a quadrilateral ABCD in which: $∠ A = 120^{\circ}, ∠ B = 60^{\circ}, ∠ AB = 4 c m, B C = 4.5 c m and C D = 5 c m .$

A B C D

A B ∥ C D, A B = 5 c m, ∠ B = 80^{o}, B C = 4 c m

A D = 4.5 c m

A, B, C, D

A B = 5.8 c m

B D = 5 c m

A B = 3.8 c m

B C = 5.5 c m

C D = 4.5 c m

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