Construct a quadrilateralABCDin which AB =5 cm, BC = 4 cm, CD = 6 cm and AD = 5 cm and diagonal AC = 7.8

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Solution

Steps of Construction:
1. Draw line segment AB with length 5cm.
2. Measure arc of length 4cm and taking B as centre, draw an arc.
3. Draw another arc of length 7.8cm taking A as centre. Name the point of intersection as C.
4. With C as centre draw an arc of length 6cm and with A as centre draw arc of length 5cm. Name the point of intersection as D.

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Similar questions

A B C D

A B = 5 c m, B C = 4 c m; C D = 7 c m, A D = 6 c m

B D = 5 c m

A (□ A B C D)

4 (3 + \sqrt{6}) c m^{2}

We can construct an unique quadrilateral ABCD with AB = 4 cm, BC = 6 cm, AC = 7 cm, CD = 5 cm and BD = 8 cm.

Construction of a unique quadrilateral ABCD is possible with AB = 4cm, BC = 6cm, AC = 7cm, CD = 5cm and BD = 8cm.

Construct a quadrliateral ABCD; if:

(i) AB = 4.3 cm, BC = 5.4, CD = 5 cm, DA = 4.8 cm and $∠$ ABC = $75^{\circ}$ .

(ii) AB = 6 cm, CD = 4.5 cm, BC = AD = 5 cm and $∠ BCD = 60^{\circ}$

(iii) AB = 8 cm, BC = 5.4 cm, AD = 6 cm, $∠ A = 60^{\circ}$ and $∠ B = 75^{\circ}$ .

(iv) AB = 5 cm, BC = 6.5 cm, CD = 4.8 cm, $∠ B = 75^{\circ}$ and $∠ C = 120^{\circ}$

(v) AB = 6 cm = AC, BC = 4 cm, CD = 5 cm and AD = 4.5 cm.

(vi) AB = AD = 5 cm, BD = 7 cm and BC = DC = 5.5 cm

Construct quadrilateral ABCD given BC = 4.5 cm, AD = 5.5 cm, CD = 5 cm, diagonal AC = 5.5 cm and diagonal BD = 7 cm.

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