Question

Construct a quadrilateral ABCD in which AB = BC = 3 cm, AD = 5 cm,$\angle A={90}^{\circ }$ and $\angle B={105}^{\circ }.$

Answer 1

Steps of construction:

Step (1): Draw AB = 3 cm.

Step (2): Construct $\angle DAB={90}^{\circ }$

Step (3) : With A as the center and radius 5 cm, cut off AD = 5 cm.

Step (4) : Construct $\angle ABC={105}^{\circ }.$

Step (5): With B as the center and radius 3 cm, cut off BC = 3 cm.

Step (6). Join CD