Question

Construct a quadrilateral $ABCD$, when :
Angle $A={90}^{o}AB=4.6$ cm, $BD=6.4$ cm, $AC=6$ cm and $CD=4.2$ cm.

Answer 1

$\Rightarrow$ Draw a line segment $AB=4.6cm$

$\Rightarrow$ Take $A$ as center and draw an angle of ${90}^o$.

$\Rightarrow$ $BD=6.4cm$

$\Rightarrow$ Take $A$ as center with radius $6cm$ and draw an arc.

$\Rightarrow$ Take $D$ as center with radius $4.2cm$ and draw an arc, which cuts off previous arc at point $C.$

$\Rightarrow$ Join $BC,CD,AC$ and $BD$.

$\therefore$ $ABCD$ is a required quadrilateral.