Question

Construct a quadrilateral $ABCD$ with the following measures:
$l\left(AB\right)=6.4cm,l\left(BC\right)=4.8cm,\angle A={70}^o,\angle B={50}^o,\angle C={140}^o$.

Answer 1

Following are the construction steps:

(1). Draw a line segment $AB=6.4cm$

(2). Take $A$ as center and draw angle of ${70}^o$.

(3). Take $B$ as center and draw angle of ${50}^o$.

(4). Take $B$ as centre and cut an arc of $4.8cm$ on the ${50}^o$ angle line. It intersects at $C$. Hence, $BC=4.8cm$.

(5). Take $C$ as center and draw angle angle of ${140}^o$, which meets $\angle A$ at point $D.$

Hence, $ABCD$ is the required quadrilateral.