Question

Construct a quadrilateral $ABNV$ where $AV=7cm,BA=8cm,BN=10cm,NV=5cm$ and $BV=11cm.$

The relation between diag. $AN$ and diag. $BV$ is

• A. $AN>BV$
• B. $AN<BV$
• C. $AN=BV$
• D. None of the above

Answer 1

The correct option is B $AN<BV$

1. Draw a line segment $BV=11cm$.

2. With $10cm$ as radius, draw an arc from $B$.

3. Similarly, with radius as $5$ cm from $V$, cut the arc just drawn.

4. They will intersect at $N$. Join $BN$ and $VN$.

5. With $7cm$ as radius, draw an arc from $V$. Similarly, with radius as $8cm$ from $B$, cut the arc just drawn.

6. They will intersect at $A$. Join $AB$ and $VA$.

7. $ABNV$ is the required quadrilateral.

8. Upon measuring the distance between $A$ and $N$, we get $AN=10cm$

Therefore, $BV>AN$