wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Construct a quadrilateral ABNV where AV=7 cm,BA=8 cm,BN=10 cm,NV=5 cm and BV=11 cm.
Then, the perimeter of ΔBNV is

A
26 cm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
24 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
28 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
22 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 26 cm
1. Draw a line segment BV=11 cm.
2. With 10 cm as radius, draw an arc from B.
3. Similarly, with radius as 5 cm from V, cut the arc just drawn.
4. They will intersect at N. Join BN and VN.
5. With 7 cm as radius, draw an arc from V. Similarly, with radius as 8 cm from B, cut the arc just drawn.
6. They will intersect at A. Join AB and VA.
7. ABNV is the required quadrilateral.

Perimeter of BNV=BN+NV+BV=10+5+11=26 cm

595923_528569_ans.png

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Trapezium
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon