Question

Construct a quadrilateral BDEF where DE=4.5 cm, EF=3.5 cm, FB=6.5 cm,and $\angle F={50}^{\circ }$ and $\angle E={100}^{\circ }$

Answer 1

(i) Draw a line segment EF= 3.5 cm.
(ii) At E, draw a ray EX making an angle of ${100}^{\circ }$ and cut off ED=4.5 cm.
(iii) At $F,$ draw another ray $FY$making an angle of ${45}^{\circ }$ and cut off FB=6.5 cm.
(iv) Join $DB,$

Then BDEF is the required quadrilateral.