Construct a quadrilateral PQRS in which PQ = 6 cm, QR = 5.6 cm, RS = 2.7 cm, ∠Q = 45° and ∠R = 90°.

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Solution

Steps of construction:
Step 1: Draw QR= $5.6 c m$
Step 2: Make $∠ Q = 45^{\circ} and ∠ R = 90^{\circ}$
Step 3: With Q as the centre, draw an arc of $6 c m$ . Name that point as P.
Step 4: With R as the centre, draw an arc of $2.7 c m$ . Name that point as S.
Step 6: Join P and S.
Then, $P Q R S$ is the required quadrilateral.

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Construct a quadrilateral PQRS in which PQ = 6 cm, QR = 5.6 cm, RS = 2.7 cm, $∠ Q = 45^{\circ}$ and $∠ R = 90^{\circ}$ .

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P Q R S

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and

∠ R = 80^{o}

PQRS is a quadrilateral in which $P Q = 5 \sqrt{2} c m$ , $Q R = 5 \sqrt{2} c m$ , $R S = 8 c m$ , $S P = 6 c m$ , $∠ P S R = ∠ P Q R = 90^{\circ}$ . Then its area is

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Construct a quadrilateral PQRS in which PQ = 6 cm, QR = 5.6 cm, RS = 2.7 cm, ∠Q = 45° and ∠R = 90°.

Steps of construction: Step 1: Draw QR= 5.6 cm Step 2: Make ∠Q=45∘ and ∠R=90∘ Step 3: With Q as the centre, draw an arc of 6 cm. Name that point as P. Step 4: With R as the centre, draw an arc of 2.7cm. Name that point as S. Step 6: Join P and S. Then, PQRS is the required quadrilateral.