Construct a quadrilateral $P Q R S$ such that $P Q = 3.5 c m, Q R = 4.5 c m, R S = 4 c m, ∠ Q = 110^{o}$ and $∠ R = 80^{o}$ .

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Solution

$\Rightarrow$ Draw a line segment QR = 4.5cm.
$\Rightarrow$ Construct angles 110 $^{\circ}$ and 80 $^{\circ}$ at points Q and R.
$\Rightarrow$ Cut off PQ = 3.5cm.
$\Rightarrow$ Cut off RS = 4cm.
$\Rightarrow$ Join PS.
Thus, PQRS is a required quadrilateral.

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