Question

Construct a quadrilateral PQRS, where $\dot{PQ}=7.7cm,QR=6.8cm,RS=5.1cm,SP=3.6cm$ and $\angle R={120}^{\circ }$.

Answer 1

$\Rightarrow$ Draw a line segment $QR=6.8cm$

$\Rightarrow$ Take $R$ as center and draw an angle of ${120}^o.$

$\Rightarrow$ Cut off $RS=5.1cm$

$\Rightarrow$ Take $S$ as center with radius $3.6cm$ and draw an arc.

$\Rightarrow$ Take $Q$ as center with radius $7.7cm$ and draw an arc, which intersects previous arc at point $P$.

$\Rightarrow$ Join $PS$ and $PQ$

$\therefore$ $PQRS$ is an required quadrilateral.