Question

# Construct a quadrilateral PQRS, where $$\dot { P Q } = 7.7 \mathrm { cm } , Q R = 6.8 \mathrm { cm } , R S = 5.1 \mathrm { cm } , S P = 3.6 \mathrm { cm }$$ and $$\angle R = 120 ^ { \circ }$$.

Solution

## $$\Rightarrow$$  Draw a line segment $$QR=6.8\,cm$$$$\Rightarrow$$  Take $$R$$ as center and draw an angle of $$120^o.$$$$\Rightarrow$$  Cut off $$RS=5.1\,cm$$$$\Rightarrow$$  Take $$S$$ as center with radius $$3.6\,cm$$ and draw an arc.$$\Rightarrow$$  Take $$Q$$ as center with radius $$7.7\,cm$$ and draw an arc, which intersects previous arc at point $$P$$.$$\Rightarrow$$  Join $$PS$$ and $$PQ$$$$\therefore$$  $$PQRS$$ is an required quadrilateral.Mathematics

Suggest Corrections

0

Similar questions
View More

People also searched for
View More